Question

Find the roots of the polynomial equation.

x2 + 2x – 48 = 0


A.
–6, 8

B.
–4, 12

C.
–12, –4

D.
–8, 6

Answer 1

@Mateaus

Answer 2

First factor then set them equal to 0

Answer 3

x2+(8-6)x-48 open bracket factor it

Answer 4

O_O no

Answer 5

\[x^2 + 2x -48 = 0\]

Answer 6

im not good at math:(

Answer 7

I'm actually really bad at explaining factorials x_x

Answer 8

(x+8)(x-6)

Answer 9

then you set them to =0
x+8 = 0 x-6 = 0

Answer 10

solve for both x's

Answer 11

help:(..

Answer 12

I am bad at explaining too, but here's my shot;\[(x+a)(x+b) = x^2+(a+b)x+ab,~~~\text{Right?}\]
Since you are given \(x^2+2x-48\), you have you have \(a+b=2\) and \(ab=-48\)

Can you figure out what \(a\) and \(b\) is?