Question

Multivariable Calculus Question:

(see photo)

By the way, the plane that it asks for from the "previous problem" is the plane in the photo.

Answer 1

is there more information about that plane, what is vector n, and point Q

Answer 2

No, that's it. That's the thing. I felt like there was missing information, but I didn't know if I was wrong. Probably there is.

Answer 3

I asked my professor about it. I haven't received a response yet.

Answer 4

This was the previous question, but I have the answer to it already. It's <11,-12,14>:

Answer 5

should be
<11,-12,-14>

Answer 6

let me double check that, one moment

Answer 7

Okay

Answer 8

Wait, you are right. I typed it wrongly.

Answer 9

so looks like the formula is right there, we can just plug in

Answer 10

you would like to verify ?

Answer 11

i dont like the drawing, its a little ambiguous, the way D is placed

Answer 12

I'm not too sure I see it though. Which formula is the one you are referring to, that is "there"?

Answer 13

the distance D is the length of the projection of the vector from P to Q onto the vector PD
http://prntscr.com/77hm39

Answer 14

Oh I see where D is now. (per your drawing)

Answer 15

So I use the formula that D is equal to?

Answer 16

ok maybe i misread the graph, let me draw this again, one moment

Answer 17

OH WAIT so Q is just 0?!

Answer 18

Okay

Answer 19

Q was given in the last problem , its hte point (-1,3,0)

Answer 20

Oh..... of course

Answer 21

Now what?

Answer 22

So that means no equation of the plane is needed because you can just use the normal vector?

Answer 23

right

Answer 24

Ohhhhh Okay. That makes sense! So I just use the equation for D.... Thanks for clarifying this! I agree with you that the figure could have been made better.

Answer 25

let me draw this again

Answer 26

Okay

Answer 27

:) Thanks!

Answer 28

I had one more question (not pertaining to this problem, but under the same topic). Can you help me with it?

Answer 29

Or should I start a new question?