Mathematics
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OpenStudy (anonymous):
rate of change??
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OpenStudy (anonymous):
ah welcome back @geerky42 >,<
geerky42 (geerky42):
Again just use \(\dfrac{f(b)-f(a)}{b-a}\)
So you have \(\dfrac{g(\text{-}3)-g(\text{-}1)}{\text{-}3-(\text{-}1)}\)
geerky42 (geerky42):
Can you tell me what is g(-3) and g(-1)?
OpenStudy (anonymous):
2?
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geerky42 (geerky42):
|dw:1432152173165:dw|
geerky42 (geerky42):
What is g(-3)? at x=-3
OpenStudy (anonymous):
4
geerky42 (geerky42):
Yep and g(-1)?
OpenStudy (anonymous):
2
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OpenStudy (anonymous):
-2
geerky42 (geerky42):
Correct.
So you have \(\dfrac{g(\text{-}3)-g(\text{-}1)}{\text{-}3-\text{-}1} = \dfrac{4-(\text{-}2)}{\text{-}2}\)
geerky42 (geerky42):
You can handle the rest, right?
OpenStudy (anonymous):
6/-2?
geerky42 (geerky42):
yeah, which simplifies to what?
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geerky42 (geerky42):
- (6/2)=?
OpenStudy (anonymous):
-3
geerky42 (geerky42):
There you go
OpenStudy (anonymous):
-3/-2?
geerky42 (geerky42):
average rate of change is -3
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OpenStudy (anonymous):
oh ok thankyou
geerky42 (geerky42):
no problem
OpenStudy (anonymous):
@geerky42 okay so i did one and got it right using the steps you showed me, but i have one last one i just need giduance on?
OpenStudy (anonymous):
i think its g(0)-g(3)/ 3-0= 2-1/0-3
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geerky42 (geerky42):
actually g(3) - g(0) / 3-0
geerky42 (geerky42):
denominator is clearly 3, so now for numerator;
geerky42 (geerky42):
just look at graph. What is g(3)? (at x=3)
OpenStudy (anonymous):
1
geerky42 (geerky42):
|dw:1432153100543:dw|
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OpenStudy (anonymous):
oh wait, 9
geerky42 (geerky42):
Yep. What about g(0)?
OpenStudy (anonymous):
thats at 2
geerky42 (geerky42):
Yeah, so \(\dfrac{g(3)-g(0)}{3} = \dfrac{9-2}{3}=~?\)
OpenStudy (anonymous):
7/3
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geerky42 (geerky42):
right
OpenStudy (anonymous):
and that is my answer?
geerky42 (geerky42):
Yeah.