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Mathematics 15 Online
OpenStudy (anonymous):

rate of change??

OpenStudy (anonymous):

http://gyazo.com/549c13677363530e830f76721805bbf9

OpenStudy (anonymous):

ah welcome back @geerky42 >,<

geerky42 (geerky42):

Again just use \(\dfrac{f(b)-f(a)}{b-a}\) So you have \(\dfrac{g(\text{-}3)-g(\text{-}1)}{\text{-}3-(\text{-}1)}\)

geerky42 (geerky42):

Can you tell me what is g(-3) and g(-1)?

OpenStudy (anonymous):

2?

geerky42 (geerky42):

|dw:1432152173165:dw|

geerky42 (geerky42):

What is g(-3)? at x=-3

OpenStudy (anonymous):

4

geerky42 (geerky42):

Yep and g(-1)?

OpenStudy (anonymous):

2

OpenStudy (anonymous):

-2

geerky42 (geerky42):

Correct. So you have \(\dfrac{g(\text{-}3)-g(\text{-}1)}{\text{-}3-\text{-}1} = \dfrac{4-(\text{-}2)}{\text{-}2}\)

geerky42 (geerky42):

You can handle the rest, right?

OpenStudy (anonymous):

6/-2?

geerky42 (geerky42):

yeah, which simplifies to what?

geerky42 (geerky42):

- (6/2)=?

OpenStudy (anonymous):

-3

geerky42 (geerky42):

There you go

OpenStudy (anonymous):

-3/-2?

geerky42 (geerky42):

average rate of change is -3

OpenStudy (anonymous):

oh ok thankyou

geerky42 (geerky42):

no problem

OpenStudy (anonymous):

@geerky42 okay so i did one and got it right using the steps you showed me, but i have one last one i just need giduance on?

OpenStudy (anonymous):

http://gyazo.com/b14f8a03ca21765d1753fa30b517b291

OpenStudy (anonymous):

i think its g(0)-g(3)/ 3-0= 2-1/0-3

geerky42 (geerky42):

actually g(3) - g(0) / 3-0

geerky42 (geerky42):

denominator is clearly 3, so now for numerator;

geerky42 (geerky42):

just look at graph. What is g(3)? (at x=3)

OpenStudy (anonymous):

1

geerky42 (geerky42):

|dw:1432153100543:dw|

OpenStudy (anonymous):

oh wait, 9

geerky42 (geerky42):

Yep. What about g(0)?

OpenStudy (anonymous):

thats at 2

geerky42 (geerky42):

Yeah, so \(\dfrac{g(3)-g(0)}{3} = \dfrac{9-2}{3}=~?\)

OpenStudy (anonymous):

7/3

geerky42 (geerky42):

right

OpenStudy (anonymous):

and that is my answer?

geerky42 (geerky42):

Yeah.

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