Expand (x + 3)^5. x5 + 3x4 + 9x3 + 27x2 + 81x + 243 x5 + 5x4 + 100x3 + 250x2 + 135x + 243 x5 + 15x4 + 90x3 + 270x2 + 405x + 243 x5 + 15x4 + 45x3 + 90x2 + 135x + 243
i think its c
(x-3)^5 = x^5 -15x^4 + 90x^3 - 270x^2 + 405x - 243
so is it c
@chrperez28 what u said isn't one of the answer choices
yeah its C
thanks
That's because he expanded (x-3)^5, not (x+3)^5 lol.
Expand (2x – 2y)5. 32x5 – 80x4y + 160x3y2 – 160x2y3 + 80xy4 – 32y5 32x5 + 160x4y – 320x3y2 + 320x2y3 – 160xy4 + 32y5 32x5 + 80x4y – 160x3y2 + 160x2y3 – 80xy4 + 32y5 32x5 – 160x4y + 320x3y2 – 320x2y3 + 160xy4 – 32y5
do u know this one
its D
could you tellme how to do these because i have more
Expand (5 + z)4. 625 + 500z + 150z2 + 20z3 + z4 625 + 375z + 150z2 + 15z3 + z4 625 + 250z + 100z2 + 10z3 + z4 625 + 125z + 25z2 + 5z3 + z4
i dont know this one sorry :(
what grade is this for ?
How can you not know lol?
i got something that isn't one of the options so i don't want to give him the wrong info
im a junior
Well, you can simply the expression, then you would get one of the options.
can you use pascal's triangle ?
i mean are you allowed .... ?
i am a freshmen so i don't get all of these i get some but i never learned it in my class i see what my cousin does sometimes like how she does her work that's how i get this i learned some things from looking at her doing her work
i think im allowed to
alright ready ?
yea
\[\huge\rm (5+z)^4\] what numbers are in 4th row bec exponent is 4 so then 2nd number of row should be 4
|dw:1432157571165:dw| first term exponent start from 0 and decreases to 4(given exponent ) 2nd term exponent start from (given exponent ) and end up with 0 exponent
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