Question

Cos(theta)[sec(theta)-cos(theta)]=sin^2(theta)

Answer 1

\[a(b - c) = ab - ac \]
\[\cos \theta \times \sec \theta = 1 \]

Answer 2

this ones easy

Answer 3

just put sec theta = to 1/cos theta then simply multiply

Answer 4

I don't understand your way lol

Answer 5

it will become 1 - cos^2 theta which is equal to sin^2 theta