Can someone tell me if I did this right? Given b = 12, c = 15 and A = 60° in triangle ABC, use the Law of Cosines to solve for a. Fill in the blank(s) to complete each step. If applicable, be sure to enter all decimal numbers with a zero in the ones place. Round your final answer to the nearest hundredth.
HI!!
\[\[a^2=b^2+c^2-2bc\cos(A)\] \[a^2=12^2+15^2-2\times 12\times 15\cos(60)\]
yeah \(a^2=189\)
hi @misty1212 !! :) can you please tell me if I did this problem correctly??
and so \(a=13.75\)
looks good to me not sure about all those stupid blanks you have to fill in, like you are a child painting by numbers, but your answers are right
oh yes, they are right too nice
okay can I send you screenshots of my other work and can you tell me if I did them right? I keep getting a 60 on this lesson. @misty1212
sure
this is number 1. @misty1212
this going to take a second
2.
lets do the first one first
okay :) @misty1212
i need to crank up the calculator
lol alright.
check my work, but i get \(3.5\) for the first one http://www.wolframalpha.com/input/?i=sqrt%287%5E2%2B4%5E2-2*7*4*cos%2820%29%29
yeah that's what I got too. so the problem is false @misty1212
right false
second one is another law of cosines too right?
|dw:1432172045725:dw|
i get 105, not what you got
http://www.wolframalpha.com/input/?i=sqrt%2870%5E2%2B40%5E2-2*70*40*cos%28144%29%29
i think i did it right
yeah I think so too thank you! do you know if I did this one right? @misty1212
looks like yet another law of cosines problem although we could use the law of sines too
i get 1.8 too
I though they were the same thing? @misty1212
no law of sines is easier
\[\frac{a}{\sin(A)}=\frac{b}{\sin(B)}=\frac{c}{\sin(C)}\] it is just solving ratios
no matter your answer of 1.8 looks right to me
oh okay got it. can you please help me with this one too? @misty1212
gonna law of cosines me to death!
yeah i get 7.9 so go with 8
okay :) how bout this one?
what, now i gotta read?
ok yet another law of cosines i got my template set up
i get 75
http://www.wolframalpha.com/input/?i=sqrt%2885%5E2%2B105%5E2-2*85*105cos%2845%29%29
sorry for asking for so much but honestly your help, helped me a ton thank you @misty1212
you are welcome are you done?
yeah :) I got my grade up to a 90% @misty1212 thanks once again!
yay !!\[\huge \color\magenta\heartsuit\]
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