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Mathematics 20 Online
OpenStudy (anonymous):

Can someone tell me if I did this right? Given b = 12, c = 15 and A = 60° in triangle ABC, use the Law of Cosines to solve for a. Fill in the blank(s) to complete each step. If applicable, be sure to enter all decimal numbers with a zero in the ones place. Round your final answer to the nearest hundredth.

OpenStudy (anonymous):

OpenStudy (misty1212):

HI!!

OpenStudy (misty1212):

\[\[a^2=b^2+c^2-2bc\cos(A)\] \[a^2=12^2+15^2-2\times 12\times 15\cos(60)\]

OpenStudy (misty1212):

yeah \(a^2=189\)

OpenStudy (anonymous):

hi @misty1212 !! :) can you please tell me if I did this problem correctly??

OpenStudy (misty1212):

and so \(a=13.75\)

OpenStudy (misty1212):

looks good to me not sure about all those stupid blanks you have to fill in, like you are a child painting by numbers, but your answers are right

OpenStudy (misty1212):

oh yes, they are right too nice

OpenStudy (anonymous):

okay can I send you screenshots of my other work and can you tell me if I did them right? I keep getting a 60 on this lesson. @misty1212

OpenStudy (misty1212):

sure

OpenStudy (anonymous):

this is number 1. @misty1212

OpenStudy (misty1212):

this going to take a second

OpenStudy (anonymous):

2.

OpenStudy (misty1212):

lets do the first one first

OpenStudy (anonymous):

okay :) @misty1212

OpenStudy (misty1212):

i need to crank up the calculator

OpenStudy (anonymous):

lol alright.

OpenStudy (misty1212):

check my work, but i get \(3.5\) for the first one http://www.wolframalpha.com/input/?i=sqrt%287%5E2%2B4%5E2-2*7*4*cos%2820%29%29

OpenStudy (anonymous):

yeah that's what I got too. so the problem is false @misty1212

OpenStudy (misty1212):

right false

OpenStudy (misty1212):

second one is another law of cosines too right?

OpenStudy (misty1212):

|dw:1432172045725:dw|

OpenStudy (misty1212):

i get 105, not what you got

OpenStudy (misty1212):

i think i did it right

OpenStudy (anonymous):

yeah I think so too thank you! do you know if I did this one right? @misty1212

OpenStudy (misty1212):

looks like yet another law of cosines problem although we could use the law of sines too

OpenStudy (misty1212):

i get 1.8 too

OpenStudy (anonymous):

I though they were the same thing? @misty1212

OpenStudy (misty1212):

no law of sines is easier

OpenStudy (misty1212):

\[\frac{a}{\sin(A)}=\frac{b}{\sin(B)}=\frac{c}{\sin(C)}\] it is just solving ratios

OpenStudy (misty1212):

no matter your answer of 1.8 looks right to me

OpenStudy (anonymous):

oh okay got it. can you please help me with this one too? @misty1212

OpenStudy (misty1212):

gonna law of cosines me to death!

OpenStudy (misty1212):

yeah i get 7.9 so go with 8

OpenStudy (anonymous):

okay :) how bout this one?

OpenStudy (misty1212):

what, now i gotta read?

OpenStudy (misty1212):

ok yet another law of cosines i got my template set up

OpenStudy (misty1212):

i get 75

OpenStudy (anonymous):

sorry for asking for so much but honestly your help, helped me a ton thank you @misty1212

OpenStudy (misty1212):

you are welcome are you done?

OpenStudy (anonymous):

yeah :) I got my grade up to a 90% @misty1212 thanks once again!

OpenStudy (misty1212):

yay !!\[\huge \color\magenta\heartsuit\]

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