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Mathematics 14 Online
OpenStudy (thats_kyy):

Is This Right?

OpenStudy (thats_kyy):

OpenStudy (thats_kyy):

@Nnesha

OpenStudy (thats_kyy):

@rational

OpenStudy (misty1212):

lol does that really say "simplify"??!!

OpenStudy (misty1212):

what idiot math teacher wrote this? means "solve for \(n\)"

OpenStudy (misty1212):

if you multiply both sides by 5 you get \[4n-1=2n\]

OpenStudy (thats_kyy):

mhm

OpenStudy (misty1212):

so no your answer is not right

OpenStudy (misty1212):

\[4n-1=2n\\ 2n-1=0\\ 2n=1\] are the first three steps

OpenStudy (misty1212):

i still can't believe it says "simplify" who wrote this? FLVS? some other on line system?

OpenStudy (skullpatrol):

The question asks for the simplified form of the equation, which is the form of the equation in which the solution or solutions can easily be seen. That is, an equivalent equation that has the same solution set as the original equation.

OpenStudy (skullpatrol):

You see, the answer is n = 1/2 because when n is replaced by 1/2 you get the true statement 1/2 = 1/2; which means the number 1/2 satisfies the original equation and thus is a solution or root of the equation. This also shows why you can go back to the original equation and substitute 1/2 for n in it to check your work to see if you still get a true statement.

OpenStudy (skullpatrol):

$$\Huge \dfrac{4n}{5}—\dfrac{1}{5}=\dfrac{2n}{5}$$ $$\Huge \dfrac{4(1/2)}{5}—\dfrac{1}{5}=\dfrac{2(1/2)}{5}$$ $$\Huge \dfrac{2}{5}—\dfrac{1}{5}=\dfrac{1}{5}$$ $$\Huge \dfrac{1}{5}=\dfrac{1}{5}$$

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