Question

Can someone help me turn (-5,0) (0,2) in a function equation?

Answer 1

@AJ01

Answer 2

find the slope m= (y2-y1)/(x2-x1)
then y-y1=m(x-x1)

Answer 3

Yea I tried I couldnt figure it out...

Answer 4

m=(2-0)/(0-(-5))=2/5

Answer 5

y-0=2/5(x-(-5))
y=2/5x+2

Answer 6

This is what I am doing

Answer 7

I'm pretty sure I did b right, but I am stuck on c

Answer 8

do as above

Answer 9

I graphed (-2,0) (0,2) for a.
Then I graphed (-5,0) (0,2) for b.
Now I am stuck in c & I am not sure if I did b right.

Answer 10

find the 2 points from the plot

Answer 11

What do you mean? I graphed the 2 points in paint...

Answer 12

So it would be g(x)=2/5x+2?

Answer 13

graph b

Answer 14

I did graph b.. I got (-5,0) (0,2)

Answer 15

the points (0,2) and (-5,0)

Answer 16

Did you see the screen shot?

Answer 17

this is the same as above so i am looking to your answer for part a and b......
a is wrong f(x) cannot be negative

Answer 18

Okay so C would be g(x)=2/5x+2?

Answer 19

yes but this if you did part b right!

Answer 20

Can you check?

Answer 21

the plot just shifted by 3 unit x->x-3

Answer 22

now find 2 points

Answer 23

Would it be -5 or 1?

Answer 24

because -2 - 3 is -5

Answer 25

this one has nothing to do with your first question

f(x)=|x+2|
x->x-3
y->y
so
g(x)=|x-3+2|
g(x)=|x-1|