WILL FANN & MEDALL
You roll a standard number cube. Find P (number greater than 2).
a. 2/3
b. 5/6
c. 6/5
d. 3/2
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OpenStudy (anonymous):
@triciaal
OpenStudy (michele_laino):
possible cases are
1, 2, 3, 4, 5 , 6
namely we have 6 possible cases, whreas
favorable cases are:
3, 4, 5, 6
so we have 4 favorable cases.
Then the probability P, is:
P= favorable cases/ possible cases=...?
OpenStudy (michele_laino):
whereas*
OpenStudy (triciaal):
possible numbers on a cube are .......
what numbers are greater than 2?
how many numbers greater than 2 compared with the total possibilities
OpenStudy (anonymous):
would it be.... b or a?
@triciaal @Michele_Laino
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OpenStudy (triciaal):
review the responses above
OpenStudy (triciaal):
favorable cases/ possible cases same as how many greater than 2/ how many possible
what do you get? always reduce to the lowest terms
OpenStudy (anonymous):
4/6 = 2/3
so a?
OpenStudy (anonymous):
@triciaal
OpenStudy (triciaal):
you got it
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