Question

If sin theta = (sqrt 3)/2, which could not be the value of theta?
A. 60 degrees
B. 120 degrees
C. 240 degrees
D. 420 degrees

I know that the solutions for theta are pi/3 and 2pi/3, but how does that correlate?

Answer 1

\[\sin ^{-1}\left(\frac{\sqrt{3}}{2}\right)=\frac{\pi }{3}=60 {}^{\circ} \]

Answer 2

Thanks! I was almost 100% sure this had something to do with the unit circle, but I wasn't quite sure.

Answer 3

Thank you for the medal.