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Mathematics 15 Online
OpenStudy (anonymous):

Matrix Multiplication

OpenStudy (anonymous):

OpenStudy (anonymous):

@KendrickLamar2014

OpenStudy (kendricklamar2014):

Can you try to solve it or do you need me to show you?

OpenStudy (anonymous):

give me a sec to look at it

OpenStudy (kendricklamar2014):

Ok

OpenStudy (anonymous):

Ok so would I multiply each number in the first matrix by 2?

OpenStudy (kendricklamar2014):

all the numbers in the matrix are the variable x. So you would do: 2 x(# in the matrix) + 2

OpenStudy (anonymous):

ohhhhhh! ok give me a sec

OpenStudy (kendricklamar2014):

:)

OpenStudy (anonymous):

so after multiplying each number by 2, would I add 2 to each of them?

OpenStudy (anonymous):

how does the + 2 fit in?

OpenStudy (kendricklamar2014):

Let me do the 1st one: The 1st number in the Matrix is 2. So you would do: 2*2+2 4+2 6

OpenStudy (anonymous):

sorry, like this? 6 -14 -6 6

OpenStudy (kendricklamar2014):

Yes

OpenStudy (anonymous):

ok but there's an = sign between them...

OpenStudy (anonymous):

so what answer am I looking for?

OpenStudy (isaiah.feynman):

How about writing the matrices as just A and B, and solving for x as in algebra.

OpenStudy (kendricklamar2014):

^

OpenStudy (anonymous):

whoa ok I'm lost already

OpenStudy (isaiah.feynman):

\[2X+2A = B\]

OpenStudy (kendricklamar2014):

ohh i was doing it wrong :( sorry

OpenStudy (anonymous):

its fine @KendrickLamar2014 you were trying :)

OpenStudy (isaiah.feynman):

Then we can solve for x from here, like so...\[X = \frac{ 1 }{ 2 }\left( B-2A \right)\]

OpenStudy (anonymous):

ok... let me try to work it out...

OpenStudy (isaiah.feynman):

We know A and B. So, do necessary substitution.

OpenStudy (anonymous):

so the answer is B??

OpenStudy (anonymous):

0 -11 -3 -6

OpenStudy (isaiah.feynman):

I didn't solve it actually.

OpenStudy (anonymous):

oh haha well I think that's the right answer. thank you

OpenStudy (isaiah.feynman):

Welcome!

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