Question

Can I have help with this geometry question? (finding a value of a triangle) http://gyazo.com/9255df7ddde4c79af6e63a2fc0b09998

Answer 1

did you select that randomly?

Answer 2

yeah, when trying to screenshot the problem i accidentally clicked that

Answer 3

do you know your trig function definitions?

Answer 4

soh
cah
toa

Answer 5

somewhat, not well though. would need help setting up the equation

Answer 6

you're given an angle and 2 sides. do you know which they are?
after that, you should be able to pick out one of the relationships

Answer 7

what do you mean? o:

Answer 8

ok, we're given an angle, 43 deg
and 2 sides, a, and 6

we have to find a trig function that when applied to 43, uses those sides

Answer 9

(lost connection sorry!)
and how would i set it up and which one would i use (coh, cah, toa)?

Answer 10

sin uses opp and hypotenuse
cosine uses adjacent and hypotenuse
tangent uses opposite and adjacent

the hypotenuse of a right triangle is always the side opposite the right angle
the opposite side of 43 should be obvious to you
the adjacent is the only one that's left

then you pick one out that fits the information we have

Answer 11

so if its tan then, i would do 43/6 then plug that into tan() to get a?

Answer 12

43 is an angle, I'm not sure what you did

Answer 13

mkay. this is pretty new to me, and my course i'm taking doesn't explain it well, at all, so i'm confused then..

Answer 14

yeah I'm typing something, dw. don't get disheartened if I sound rude or impatient mayne

Answer 15

basically, what we want is either \(\sin(43), \cos(43),\) or\(, \tan(43)\)
we don't have the hypotenuse so we can instantly cancel out sin and cos

that leaves us with \(\tan(43)=\dfrac{?}{?}\)

tan = opposite/adjacent? correct?

Answer 16

okay, tan(40)=6/a?