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Solve for x logx+log(x-1)-log(4x)
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Hm, is there an equals sign in there somewhere?
Ooops!! logx+log(x-1)=log(4x)
@JoannaBlackwelder
Ah, that makes more sense. :-) Any ideas how to start?
Uhm....no lol
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Ok, no worries. We need to combine the logs on the left side.
loga + logb = log(ab)
Can you use that formula?
Got it so logx multiplies by log(x-1) which is log x(x-1) right?
Yep, great!
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So, we have log x(x-1) = log (4x)
Any thoughts from here?
Maybe multiply the left side
to get log (x^2-1)
Multiplying sounds good. But check your distributing.
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Wait so then would it be x^2-x??
log x^2-x?
Yep :-)
Ok, so, any ideas on the next step?
divide by 4 on the left side?
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Hm, no, we can't divide. Because we still have logs.
Okay well...
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