Question

how do you solve this : m^2 -2m+1= 9

Answer 1

set it equal to 0
so subtract 9 both sides

Answer 2

\[\huge\rm m^2 -2m +1 \color{Red}{-9} =0\]
1-9 = -8
\[\huge\rm m^2 -2m -8 =0\]
now find two number if you multiply them you should get product of AC(a is leading coefficient and C is constant term of the equation ) and if you add or subtract them you should get middle term
a b c are \[\large\rm \color{ReD}{A}x^2 + \color{red}{B}x+\color{red}{C}=0\]

Answer 3

\[\large \rm \color{green}{1}m^2 \color{green}{-2}m \color{green}{-8} =0\]\[\large\rm \color{ReD}{A}x^2 + \color{red}{B}x+\color{red}{C}=0\]

Answer 4

m = -2 or 4

Answer 5

@RKSSA sorry but your answer is wrong ._.