how would i solve this ? anyone know the steps ?
15^2 - 15t -30 = 0
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OpenStudy (anonymous):
factor ?
OpenStudy (skullpatrol):
Factor out 15 first
OpenStudy (unofficialllyy):
Exponents first. Use PEMDAS
OpenStudy (unofficialllyy):
Parenthesis, Exponents, Multiplication, Division, Addition, then Subtraction.
geerky42 (geerky42):
@kisntell16 You mean \(15t^2 - 15t -30 = 0\), right?
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OpenStudy (anonymous):
so i got 3t^ - 5t- 5=0 from factoring 15
OpenStudy (anonymous):
and yes c: @geerky42
OpenStudy (unofficialllyy):
Oh, well then never mind about my answer lol.
OpenStudy (unofficialllyy):
Good luck!
OpenStudy (anonymous):
oh ok but thanks tho c: @Unofficialllyy
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OpenStudy (anonymous):
well wait how did you do it tho ? show me maybe im wrong @Unofficialllyy
OpenStudy (skullpatrol):
Factor out 15
OpenStudy (anonymous):
yeah an i got 3t^ -5t-5=0 @skullpatrol
OpenStudy (skullpatrol):
Try again please
OpenStudy (unofficialllyy):
I thought your question was \[15^{2}-15t-30=0\] and if that was the case, you would do 15^2 first, since there are no parenthesis and that is the exponent. But you said the question was different.
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OpenStudy (anonymous):
well i divided a 5 out of all of it 5 \15^, and 15t and 5/-30 @skullpatrol
OpenStudy (anonymous):
and no youre right thats the question i was asking ? sorry people were confusing me @Unofficialllyy
OpenStudy (skullpatrol):
Divide each term by 15
OpenStudy (unofficialllyy):
Well first you would do 15^2
OpenStudy (anonymous):
ok well in tht case i got t^-1t-2=0 from that @skullpatrol
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OpenStudy (unofficialllyy):
I'm confused. What is the original question?
OpenStudy (anonymous):
the one you put down was the original @Unofficialllyy
OpenStudy (skullpatrol):
Now factor $$\Huge t^2-t-2$$
OpenStudy (anonymous):
it just told me to solve @Unofficialllyy
OpenStudy (anonymous):
how ? @skullpatrol
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OpenStudy (unofficialllyy):
I have to go, I'm sorry. Hopefully @skullpatrol can help!
OpenStudy (anonymous):
i hope so too haha ! but thanks for trying c: @Unofficialllyy
OpenStudy (skullpatrol):
Look for factors of -2 that add up to -1.
OpenStudy (anonymous):
i factor and i got (x-2) and (x + 1)
OpenStudy (anonymous):
@skullpatrol
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OpenStudy (skullpatrol):
Very good :)
Now your equation looks like (x-2)(x+1)=0
OpenStudy (anonymous):
so i did it c:? !!
OpenStudy (anonymous):
@skullpatrol
OpenStudy (anonymous):
one last step lol
OpenStudy (skullpatrol):
Either x-2=0 or x+1=0
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OpenStudy (anonymous):
what do you mean ?? haha @jrain35
OpenStudy (anonymous):
thanyouc: @skullpatrol
OpenStudy (skullpatrol):
The values of x that will make (x-2)(x+1)=0 a true statement.
Are 2 and -1.