Question

can someone please help me figure this problem out?
I'm suppose to find the length of a(lowercase a)

Answer 1

I think you might be able to use either the law of sines or cosines... I'm still thinking on it though

Answer 2

Oh there you go! I got it!
So, you gotta use this formula:
Law of Cosines

\[a^2 = c^2 + b^2 - 2bc *Cos A\]

Answer 3

In this case, c=11, b=13, and A=110

Answer 4

so you just plug it in and then take a square of the answer and you're all done :)

Answer 5

Hope that helped!

Answer 6

I plugged it in and got a= 19.69, -19.69 ?

Answer 7

You got a negative answer for a^2 ?

Answer 8

Yeah that's right, you get 19.69, its not negative. So length a = 19.69

Answer 9

and then I do \[\sqrt{19.69}\]?

Answer 10

Nope, \[a^2 = 387.817761\] and when you square it you get 19.69

Answer 11

oh okay. so 19.69 is my final answer?

Answer 12

Yep :)

Answer 13

will you help me with some more?

Answer 14

I'd love to, but unfortunately i gotta go get my homework done!

Answer 15

XD okay thank you!

Answer 16

No problem! :D good luck!