Question

Find all the zeros of the equation
-2x^4+27x^2+1200=0

Answer 1

-3(x^4 - 9x^2 - 400) = 0

Answer 2

What would the zeros be?

Answer 3

was that a typo in the original ?

Answer 4

-3(x^4 - 9x^2 - 400) = 0
-3(x^2 - 25)(x^2 + 16) = 0

Answer 5

Is that the answer?

Answer 6

Yes actually is was a typo oops

Answer 7

x^2 - 25 = 0
x = 5, -5

Answer 8

Supposed to be -3 in the beginning

Answer 9

the highest power of x is four so you will have 4 roots

Answer 10

x^2 + 16 = 0
x = 4i, -4i

Answer 11

Because when you set =3 equal to zero: -3 = 0
they are NOT equal to zero!

Answer 12

But when you simplify, you should write it out as:
-3(x^2 + 16)(x-5)(x+5) = 0

Answer 13

@SavineTwist write out the other 2 as well do not leave the x^2 since they ask for all the zeros

Answer 14

Thank you