Question

Can someone tell me if I am headed in the right direction with my proof?

Answer 1

one sec while I type it up

Answer 2

Suppose A is a set. Show that A is the only relation on A that is both an equivalence relation and also a function from A to A.


What I am thinking is that to show this I have to use contradiction. If you use any other relation from A to A then you will not have a function between A to A because element a_n at the end will be paired with an element a_(n-1)

Answer 3

Show that i_A ***

Answer 4

I'm not sure if this is right. It doesn't feel very rigorous

Answer 5

also i_A is the identity relation

Answer 6

help please @AccessDenied

Answer 7

@dan815 @Shorty1234