Question

Check answer? limits @perl @Hero @iambatman

Answer 1

I'm not sure because of the noncontinuous points...

Answer 2

which one would you like help with, number 1 ?

Answer 3

both please

Answer 4

for number 1, the limit exists, because the function is *approaching* the same y value from the right and left

Answer 5

http://prntscr.com/79ajlo

Answer 6

the fact that the value f(-1) is missing , doesn't matter. what matters for the limit is what the y value is approaching, as close as you want

Answer 7

Okay, thank you. So the answers would be -1 and 2, correct?

Answer 8

for number 2. the y value is approaching 1

Answer 9

oh, okay. So I ignore the other point?

Answer 10

right, because the limit doesn't care what happens at the point itself

Answer 11

the limit only cares what happens as you are getting closer, where it is going to
imagine its like a ball, where would the ball keep going if you let it go

Answer 12

Okay. Thank you. :)