simplify the rational expression, state any restrictions on the variable...t^2+t-6/t^2-9
factor numerator and denominator
\[\huge\rm (a^2 -b^2) = (a+b)(a-b)\] difference of square apply that at the denominator
t-2/t-3 t=3 t=-3? is what i got for the final
t^2 + t - 6 what are factors of this equation ?
3
just 3 ?
i mean you could go 2,3 6
so my answer up there wasnt right?
3 times -2 = - and 3-2= 1 that would be factor of t^2 + t - 6 :-)
yes that's right
t = 3 t = -3 ??? explain this plz
So its the right choice? explain what?
My brother just told me he thinks that was right, he didnt explain
so you don't know how to solve it ?
No sir, He just said i think its that one, no explaining at all. i would like to know how to though.
t^2 +t -6 find two number if you multiply them you should get -6 and if you add or subtract them you should get middle term which is one
why is it not 3, -2?
who said it's not ?
haha, okay, but those two should give us that
it is so bec leading coefficient is 1 just write it as ( t+ 3) and (t-2) this is the numerator \[\frac{ (t+3)(t-2) }{ ? }\] now denominator t^2 - 9 factor it
ok what do you mean? im sorry.
oh wait
that one gave me t+3 t-3
^^
\[\huge\rm \frac{ (t+3)(t-2) }{ (t+3)(t-3) }\] simplify
t-2/t-3
ye right now denominator can't be equal to 0 so tha'ts mean \[\huge\rm t-3 \cancel{=} 0\] solve for t
=3
not equal
And thats the final answer? :)
i know. just 3 is the restriction
\[\huge\rm t \cancel{=} 3\] bec if you plug 3 for t 3-3= 0 but we don't like 0 for this question
yes right
gO_Od to go!
If i open another would you help me? i really appreciate that!! you actually explained. i get that
i'll try :-)
Join our real-time social learning platform and learn together with your friends!