Question

Find the first four terms of the multiplication pattern given by the formula.
8 • 3^n – 1

Answer 1

@Loser66

Answer 2

Help

Answer 3

@texaschic101

Answer 4

does n starts at 0 or 1 ?

Answer 5

Uhh 1?

Answer 6

n=1 ---> 8*3^1-1 = 24-1=23
n=2 ---> 8*3^2-1 = 8*9-1=72-1=71
n=3 ---> 8*3^3-1 = 8*27-1=216-1=215
:)

Answer 7

23, 47 ,71, 95 ?

Answer 8

Wouldn't it be that..

Answer 9

@texaschic101 is that right?

Answer 10

you are doing: 8*3*n-1
you asked for 8*3^n-1

Answer 11

right..

Answer 12

So your saying the first terms are: 23,71,215 correct?

Answer 13

yes, for this formula 8*3^n-1, with n starting at 1

Answer 14

correct ^^

Answer 15

if you want the first term sub in 1 for n....second term is subbing 2 for n and so on...

Answer 16

And the last one is

Answer 17

I need four so.

Answer 18

sub in 4 for n and solve

Answer 19

haha, i had read three terms!!
you can find fourth one using n=4 :)

Answer 20

647?

Answer 21

Is that the last term.

Answer 22

yes it is

Answer 23

\[8 × 3^4 - 1 = 647\]

Answer 24

Ok

Answer 25

Thank you.

Answer 26

yw! :D

Answer 27

just remember that the n stands for the number of the term you want to find.

Answer 28

Greg mind giving texas a medal.

Answer 29

I didn't really do anything...medal is not necessary

Answer 30

sure! im new here, dont know exactly how this works...

Answer 31

Still deserve it.