Which conjunction or disjunction is equivalent to the open sentence |a – 9| ≤ 4. A. a – 9 ≥ 4 and a – 9 ≤ –4 B. a – 9 ≤ 4 or a – 9 ≥ –4 C. a – 9 ≤ 4 and a – 9 ≤ –4 D. a – 9 ≤ 4 and a – 9 ≥ –4 I have 4 other questions I need help with, most/all of them are screenshots though, I will fan and medal if you can help me with all of them.
Which conjunction or disjunction equivalent to the open sentence 4 –3|n + 2| ≥ 1? A. n + 2 ≥ 1 and n + 2 ≤ –1 B. n + 2 ≤ 1 and n + 2 ≥ –1 C. n + 2 ≤ 1 and n − 2 ≥ −1 D. n + 2 ≥ 1 or n – 2 ≤ 1
3. Solve the equation. |k + 9| = 4 A. {–13, –5} B. {–5, 5} C. {–5, 13} D. {all real numbers greater than or equal to –13 and less than or equal to –5}
4. Solve the inequality. 3 + |t + 4| < 10 A. –3 < t < 11 B. t > 3 or t < –11 C. –11 < t < 3 <--- I think its this one. D. t < 3 and t > 11
This is the last question.
@dan815 @nincompoop @hartnn @triciaal can any of yall help me. I will do anything to get help from someone. I'm in a rush cause i've been trying to figure these out for like 3 hours now.
I think maybe the first one A
Wait no B
yes, B for 1st is correct :) if you tell me how, I'll help you with 2nd question.
And I think the 3rd one is C.
so we are at 3rd one? when |a| = b, either a= b or a =-b so what can you say when |k+9| = 4 ??
Well it took me longer to answer the 2nd one but I think its D.
I meant i think the 2nd one is D
Wait no I think the 3rd one is A
lets skip the guessing work and actually solve the problem :) 3rd one : when |a| = b, either a= b or a =-b when |k+9| = 4 k+9 = 4 or k+9 = -4 can you solve for k in k+9 = 4? ?
I know -5 + 9 =4 , and -13 + 9 = -4
right, so thats how the 3rd one is A :)
now 2nd one when |a| \(\ge \)b , either a \(\ge \)b or a \(\le \) -b
4 –3|n + 2| ≥ 1 try to isolate |n+2| from that first
Is it -1
how did you get -1? very close because i got +1 |n+2| \(\le \) +1
|n+2| ≤ +1 means n+2 ≤ +1 or n+2 >= -1 which is B
Am I correct on number 4?
And for 5 i think its C.
4th is correct! :) and 5th is indeed C :)
I went ahead and submitted it and made an 80! They only one that was wrong was number 1, the correct answer was D.
oh so its an "and" instead of "or" :P and \(\Huge \mathcal{\text{Welcome }\ddot\smile} \)
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