Question

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The area of a the rectangular painting is given by the trinomial x^2+2x-15. What are possible dimensions? Use factoring

Answer 1

x^2+2x-15=0
(ax^2+bx+c=0)
(x-x1)(x+x2)
D=b^2-4*a*c
D=4+60=64
x1=(-b-sqrt(D))/2*x=(-2-8)/2*1=(-10)/2=-5
x2=(-b+sqrt(D))/2*x=(-2+8)/2=6/2=3
so, (x+5)(x-3)

Answer 2

ohh, darn. You could have said to use that formula. I just forgot. Hey, can you help me with one more?

Answer 3

yup

Answer 4

Alright! How many number solutions does the equation have?
y=3x^2-5x-5

Answer 5

every square equation (ax^2+bx+c) has 2 solutions for 3x^2-5x-5 the solutions are
x1=(5-sqrt(85))/6 & x2=x1=(5+sqrt(85))/6

Answer 6

ok, square equation. two solutions. Got it. Hey, do you know how do you find the solutions of a system. I want to try it out myself with this question I'm on

Answer 7

x2=(5+sqrt(85))/6 a mistake (the x1)
yeah, whats the question?

Answer 8

It's y=2x+2

Answer 9

x1=(5-sqrt(85))/6 & x2=(5+sqrt(85))/6 <--- it should be like that (omg somthings wrong with me )

and the other equation of the system?

Answer 10

y=x^2+3x-4

Answer 11

alright, so I'm guessing it doesnt have a solution

Answer 12

how so?

Answer 13

well...it doesnt match the answer choices

Answer 14

Nope. I'm trying to solve it too...

Answer 15

what are the solutions?

Answer 16

1. (-3,6) and (2, -4)
2. (-3, -4) and (2, 6)
3. (-3, -4) and (-2, -2)
4. No solution

Answer 17

y=y
2x+2=x^2+3x-4
x^2+3x-2x-4-2=0
x^2+x-6=0
x1=-3
x2=2
or you just misspelled some '-' or '+'...

Answer 18

oh...nevermind. It's the third choice. Alright. Hey, I'm almost done with this sample work. Sorry if I'm bothering you but I'm stuck on another problem.

Answer 19

k, i need to solve this equation.

(6x^3-1x^2+1) divide (2x+1)

Answer 20

oh, no i need to find the simper form

Answer 21

simpler