OpenStudy (minthia):

what are the tangent ratio for P and Q ?

2 years ago
OpenStudy (minthia):
2 years ago

OpenStudy (anonymous):

"opposite over adjacent" for both of them

2 years ago
OpenStudy (anonymous):

for example \[\tan(Q)=\frac{5}{12}\]

2 years ago
OpenStudy (minthia):

I am so lost I tried to use the tan sin calculator and I don't know how any suggestions?

2 years ago
OpenStudy (anonymous):

lol you cannot use a calculator for this

2 years ago
OpenStudy (minthia):

don't tell me that;(

2 years ago
OpenStudy (anonymous):

here is the deal: usually when you are asked to find the value of a function, you need to know what the input is not in this case

2 years ago
OpenStudy (anonymous):

what is the length of the side opposite the angle Q?

2 years ago
OpenStudy (minthia):

5

2 years ago
OpenStudy (anonymous):

that you see from your eyes, not a calculator right?

2 years ago
OpenStudy (anonymous):

yeah it is 5, that will be the numerator what is the length of the adjacent leg to the angle Q? (the leg, not the hypotenuse)

2 years ago
OpenStudy (minthia):

12?

2 years ago
OpenStudy (anonymous):

no not 12? but \(\huge 12 !!\)

2 years ago
OpenStudy (anonymous):

ok so 12 that is the denominator

2 years ago
OpenStudy (anonymous):

that makes \[\tan(Q)=\frac{5}{12}\]

2 years ago
OpenStudy (anonymous):

you see you do not even have to know what Q is to find \(\tan(Q)\) all you need is to look at the lengths of the sides and write the "opposite over adjacent" it is not a calculator exercise

2 years ago
OpenStudy (minthia):

ok wait for the P part of the question would I do the same thing?

2 years ago
OpenStudy (anonymous):

yeah you do the same thing the answer is different, but it is still "opposite over adjacent"

2 years ago
OpenStudy (minthia):

OMG you just taught me how to do this I have like 5 more questions like this one and I cant believe you just taught me how to figure it out. my answer is TAN P 5/12 AND TAN Q 12/5 I feel like a smarty pants now

2 years ago
OpenStudy (anonymous):

glad it made sense yes, \[\tan(P)=\frac{12}{5}\]

2 years ago
OpenStudy (anonymous):

be happy to check another one for you if you like

2 years ago
OpenStudy (minthia):

Bless you really ok let me see if I can figure it out first don't help me yet:)

2 years ago
OpenStudy (anonymous):

i will be real quiet

2 years ago
OpenStudy (minthia):

no don't be cuz I just looked at it and its the same number wise but it says sin;( now what do I do?

2 years ago
OpenStudy (anonymous):

lol freak out?

2 years ago
OpenStudy (anonymous):

just kidding you are supposed to be learning the "trig ratios" sine is "opposite over hypotenuse"

2 years ago
OpenStudy (anonymous):

so for \[\sin(Q)\] put the length of the "opposite" side in the numerator, the length of the hypotenuse in the denominator

2 years ago
OpenStudy (callmekiki):

OMG! I've wanted to meet you since I first started OS!!! Congrats! 100SS. :DDD

2 years ago
OpenStudy (minthia):

13/12?

2 years ago
OpenStudy (anonymous):

lets go slow

2 years ago
OpenStudy (anonymous):

what is the length of the side "opposite" Q

2 years ago
OpenStudy (minthia):

5?

2 years ago
OpenStudy (anonymous):

yeah 5 what is the hypotenuse of that triangle (the longest side)

2 years ago
OpenStudy (minthia):

13

2 years ago
OpenStudy (anonymous):

right

2 years ago
OpenStudy (anonymous):

therefore \[\sin(Q)=\frac{5}{13}\] that is all

2 years ago
OpenStudy (minthia):

You did it again ur a freaking genius!!!!!

2 years ago
OpenStudy (anonymous):

hardly a genius, just know the trig ratios is all

2 years ago
OpenStudy (anonymous):

\[\sin(Q)=\frac{\text{opposite}}{\text{hypotenuse}}\]\[\cos(Q)=\frac{\text{adjacent}}{\text{hypotenuse }}\]\[\tan(Q)=\frac{\text{opposite}}{\text{adjacent}}\]

2 years ago
OpenStudy (anonymous):

you need a nice cheat sheet to remember these?

2 years ago
OpenStudy (minthia):

thank you I just wrote it down I have seen it in all my books but for some reason nothing would click until I met you my life saver.

2 years ago
OpenStudy (anonymous):

(blush) yw

2 years ago
OpenStudy (minthia):

Again thank you now u made me blush;)

2 years ago
OpenStudy (anonymous):

lol good luck i can check another if you like

2 years ago
OpenStudy (minthia):

no I am good there was three like that and thanks to you I did them and feel VERY confident that they are right.

2 years ago
OpenStudy (anonymous):

whew

2 years ago
OpenStudy (minthia):

sorry I took up like an hour of your time;(

2 years ago
OpenStudy (anonymous):

oh wow now it is time for me to go watch old peoples tv (perry mason is on) ttyl

2 years ago
OpenStudy (minthia):

thanks again

2 years ago