Question

what are the tangent ratio for P and Q ?

Answer 1

"opposite over adjacent" for both of them

Answer 2

for example
\[\tan(Q)=\frac{5}{12}\]

Answer 3

I am so lost I tried to use the tan sin calculator and I don't know how any suggestions?

Answer 4

lol you cannot use a calculator for this

Answer 5

don't tell me that;(

Answer 6

here is the deal: usually when you are asked to find the value of a function, you need to know what the input is
not in this case

Answer 7

what is the length of the side opposite the angle Q?

Answer 8

5

Answer 9

that you see from your eyes, not a calculator right?

Answer 10

yeah it is 5, that will be the numerator
what is the length of the adjacent leg to the angle Q? (the leg, not the hypotenuse)

Answer 11

12?

Answer 12

no not 12? but \(\huge 12 !!\)

Answer 13

ok so 12 that is the denominator

Answer 14

that makes
\[\tan(Q)=\frac{5}{12}\]

Answer 15

you see you do not even have to know what Q is to find \(\tan(Q)\) all you need is to look at the lengths of the sides and write the "opposite over adjacent"
it is not a calculator exercise

Answer 16

ok wait for the P part of the question would I do the same thing?

Answer 17

yeah you do the same thing
the answer is different, but it is still "opposite over adjacent"

Answer 18

OMG you just taught me how to do this I have like 5 more questions like this one and I cant believe you just taught me how to figure it out. my answer is TAN P 5/12 AND TAN Q 12/5 I feel like a smarty pants now

Answer 19

glad it made sense
yes, \[\tan(P)=\frac{12}{5}\]

Answer 20

be happy to check another one for you if you like

Answer 21

Bless you really ok let me see if I can figure it out first don't help me yet:)

Answer 22

i will be real quiet

Answer 23

no don't be cuz I just looked at it and its the same number wise but it says sin;( now what do I do?

Answer 24

lol freak out?

Answer 25

just kidding you are supposed to be learning the "trig ratios"
sine is "opposite over hypotenuse"

Answer 26

so for \[\sin(Q)\] put the length of the "opposite" side in the numerator, the length of the hypotenuse in the denominator

Answer 27

OMG! I've wanted to meet you since I first started OS!!! Congrats! 100SS. :DDD

Answer 28

13/12?

Answer 29

lets go slow

Answer 30

what is the length of the side "opposite" Q

Answer 31

5?

Answer 32

yeah 5
what is the hypotenuse of that triangle (the longest side)

Answer 33

13

Answer 34

right

Answer 35

therefore \[\sin(Q)=\frac{5}{13}\] that is all

Answer 36

You did it again ur a freaking genius!!!!!

Answer 37

hardly a genius, just know the trig ratios is all

Answer 38

\[\sin(Q)=\frac{\text{opposite}}{\text{hypotenuse}}\]\[\cos(Q)=\frac{\text{adjacent}}{\text{hypotenuse }}\]\[\tan(Q)=\frac{\text{opposite}}{\text{adjacent}}\]

Answer 39

you need a nice cheat sheet to remember these?

Answer 40

thank you I just wrote it down I have seen it in all my books but for some reason nothing would click until I met you my life saver.

Answer 41

(blush)
yw

Answer 42

Again thank you now u made me blush;)

Answer 43

lol good luck
i can check another if you like

Answer 44

no I am good there was three like that and thanks to you I did them and feel VERY confident that they are right.

Answer 45

whew

Answer 46

sorry I took up like an hour of your time;(

Answer 47

oh wow
now it is time for me to go watch old peoples tv (perry mason is on)
ttyl

Answer 48

thanks again