Mathematics
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OpenStudy (anonymous):
What is the distance between points (4, −7) and (−5, 9)? Round to the nearest tenth of a unit.
units
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OpenStudy (anonymous):
@Michele_Laino
OpenStudy (anonymous):
what do you think it is?
hartnn (hartnn):
Distance between points (x1,y1) and (x2,y2) is
\(\huge d=\sqrt{(x_1-x_2)^2+(y_1-y_2)^2}\)
does this help ??
OpenStudy (anonymous):
i got 11.3 but it wont let me tpe the whole thing in
OpenStudy (anonymous):
noooo its kakarot
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OpenStudy (anonymous):
and yea but what do i plug in?
hartnn (hartnn):
yeah I am both :)
hartnn (hartnn):
so you first find x1,x2,y1,y2 values
4,-7 means x1 = 4, y1= -7
hartnn (hartnn):
x2, y2 = -5,9
x2 = -5
y2 =9
OpenStudy (anonymous):
ohhhh
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hartnn (hartnn):
4 - (-5) = ..?
then square it
-7-9 = ...?
then square it
hartnn (hartnn):
lets complete cvliboi's question first :)
OpenStudy (anonymous):
9 and -16
hartnn (hartnn):
yep, now square them
OpenStudy (anonymous):
81 and 256
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hartnn (hartnn):
add them and take the square root
that will be it!
hartnn (hartnn):
you too :)
OpenStudy (anonymous):
c;
OpenStudy (anonymous):
18.3?
hartnn (hartnn):
very close,
its 18.4 :)
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OpenStudy (anonymous):
i cant put any decimals so just 18?
hartnn (hartnn):
thats right! :)
OpenStudy (anonymous):
thanks
hartnn (hartnn):
welcome ^_^