Mathematics
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OpenStudy (anonymous):
please help me
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OpenStudy (anonymous):
OpenStudy (anonymous):
@perl is familier with it! :-)
OpenStudy (tkhunny):
Very bad question. FAR too subjective. Measure the radial width of the crust vs. the total radius.
OpenStudy (anonymous):
@perl knows this
OpenStudy (perl):
what is the radius of this pizza, or the diameter
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OpenStudy (anonymous):
it is 16 inches diameter
OpenStudy (anonymous):
large
OpenStudy (anonymous):
medium is 12 inches diameter
OpenStudy (anonymous):
ya
OpenStudy (perl):
and we need to cut off the top
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OpenStudy (anonymous):
yup
OpenStudy (perl):
we can make a crude approximation
we have an isosceles triangle
OpenStudy (anonymous):
ok
OpenStudy (perl):
Area of crust cut off = total area of sector - area of isosceles triangle
OpenStudy (perl):
Area of sector = 1/6 * π r^2 , since we have 6 slices
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OpenStudy (perl):
Area of isosceles triangle, this is going to be an equilateral triangle , since the vertex angle is 360/6 = 60 , and the base angles are congruent
OpenStudy (perl):
|dw:1432760771917:dw|
OpenStudy (perl):
you can pick any of the 6 triangles, i just chose that one
OpenStudy (anonymous):
ok
OpenStudy (perl):
|dw:1432760838050:dw|
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OpenStudy (anonymous):
what is the radius?
OpenStudy (perl):
|dw:1432760851340:dw|
OpenStudy (perl):
radius = diameter / 2 = 8
OpenStudy (anonymous):
so the diameter is 16
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OpenStudy (perl):
sorry, diameter is twice the radius
OpenStudy (perl):
radius is half the diameter
OpenStudy (anonymous):
the area of crust cut off is 26.48.
OpenStudy (anonymous):
AM i right
OpenStudy (perl):
nope
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OpenStudy (anonymous):
Area of crust cut off = total area of sector - area of isosceles triangle
A= 1/6*pi(8)^2 - 60
OpenStudy (anonymous):
27.71
OpenStudy (perl):
A= 1/6*pi(8)^2 - √(3)/ 4 (8)^2
OpenStudy (perl):
yes thats correct
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OpenStudy (anonymous):
ok I got it
OpenStudy (anonymous):
the area of the segment cut off is 5.8
OpenStudy (anonymous):
Am i right?
OpenStudy (perl):
yes, but note that this an approximation, since a pizza crust can sometimes be thick
We solved the 'ideal' problem
OpenStudy (anonymous):
ok thanks :-)
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OpenStudy (perl):
if we cut it that way
OpenStudy (perl):
so that cut approximates removing the crust
OpenStudy (anonymous):
To find the isosceles, why did u divide 360/6
OpenStudy (anonymous):
Since the triangle is 180
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OpenStudy (perl):
|dw:1432761628546:dw|