A manufacturing facility pays its employees an average wage of $4.50 an hour with a standard deviation of 50¢. If the wages are normally distributed, what is the percentage of workers getting paid between $3.75 and $5.00 an hour?
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OpenStudy (anonymous):
@myko
OpenStudy (anonymous):
@rational
OpenStudy (rational):
50 cents is same as 0.5 dollar
OpenStudy (anonymous):
Yes So im looking down the ztable at .5
OpenStudy (rational):
start by finding the zscores for observations 3.75 and 5
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OpenStudy (anonymous):
.00009
OpenStudy (rational):
mean = 4.5
standard deviation = 0.5
zscore for observation 3.75 is given by
\[\frac{3.75-4.5}{0.5} = -1.5 \]
OpenStudy (rational):
similarly try finding the zscore for obsrevation 5
OpenStudy (anonymous):
.30854
OpenStudy (rational):
how ?
show work so that il be able to pinpoint the mistake
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OpenStudy (anonymous):
OpenStudy (rational):
Nope, don't look at the ztable yet.
first we need to find zscores
OpenStudy (rational):
i have worked zscore for the observation 3.75
see if u can work the zscore for the observation 5
OpenStudy (anonymous):
So then it would just be 5-4.5/0.5=x
OpenStudy (rational):
yes what is it
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OpenStudy (anonymous):
1?
OpenStudy (rational):
Yes!
OpenStudy (rational):
so we have below so far :
zscore for observation 3.75 is ` -1.5`
zscore for observation 5 is `1`
OpenStudy (rational):
now open ur ztable, and find the areas corresponding to these zscores
OpenStudy (anonymous):
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OpenStudy (anonymous):
OpenStudy (rational):
subtract both to get the percentage of works getting paid between 3.75 and 5
OpenStudy (anonymous):
OpenStudy (rational):
area for the zscore of -1.5 is `0.06681`
area for the zscore of 1 is `0.84134`
subtract to get the percentage of workers that get paid between 3.75 and 5
OpenStudy (anonymous):
77.4%
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