Mathematics
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OpenStudy (anonymous):
Easy question for quick medal... help please.
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OpenStudy (anonymous):
There are (3^2)^4 ⋅ 3^0 bacteria in a petri dish. What is the total number of bacteria in the dish?
OpenStudy (curry):
6561
Nnesha (nnesha):
anything to the 0 power is just equal to 1 \[(2)^0 = 1\]
\[(x)^0 =1\]
another exponent rule \[\huge\rm (x^m)^n = x^{m \times n}\]
OpenStudy (anonymous):
yeah I remember that ..
@Nnesha
OpenStudy (anonymous):
@Curry that isnt right D:
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OpenStudy (curry):
well 9^4 * 1 = 6561
OpenStudy (curry):
unless i misunderstood that?
OpenStudy (anonymous):
I think you did unfort! I can give you the answer choices? But I'd like to see the work done with it ..
OpenStudy (anonymous):
A) 3^8
B) 3^9
C)3^11
D)3^24
OpenStudy (curry):
3^2 = 9 = 3 * 3
9^4 = 9*9*9*9 = 6561
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OpenStudy (curry):
well, if the base number is 3, then it'd just be 3^(2*4) = 3^8
OpenStudy (anonymous):
Ok thanks!
Nnesha (nnesha):
\[\huge\rm (x^m)^n = x^{m \times n}\]
^^^ multiply outside exponent by inside exponent of the # :-)
remember :?? :3 o^_^o
btw welcome to openstudy!
OpenStudy (anonymous):
That would give me (3^8) ⋅ 3^0 @Nnesha right?
Nnesha (nnesha):
yep right
and what's 3^0 = ?
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OpenStudy (anonymous):
1?
Nnesha (nnesha):
perfect!
OpenStudy (anonymous):
@Nnesha ahh then what would the answer be? im a little confused. is 3^8 right?
Nnesha (nnesha):
did you get 3^8 ?
OpenStudy (anonymous):
OH
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OpenStudy (anonymous):
i see
OpenStudy (anonymous):
okay, then 3^8 is right. because (3^8) x 1 = 3^8
Nnesha (nnesha):
yep right
OpenStudy (anonymous):
ahh thanks
Nnesha (nnesha):
np :-)