Question

how do i get 7 as a Pythagorean triple? please help! will medal

Answer 1

You may use the generating formulas for primitive pythagorean triples :

\(a = x^2 - y^2\)
\(b = 2xy\)
\(c = x^2 + y^2\)

Answer 2

\[x^2-y^2 = 7\]

its not so hard to solve the integers \(x,y\) because the left hand side can be factored :
\[(x+y)(x-y)=7\]
can be broken down as system of equations :
\[x+y=7\\~\\x-y=1\]
solving gives \(x=4,~y=3\)

Answer 3

oh wow that's a lot

Answer 4

plug them in the earlier generating formulas to find \(b, c\)

Answer 5

thanks ^.^