Question

I need to solve for 2x^2 -10x+3=0 using the quadratic formula. Any help?

Answer 1

I am thinking, find a,b,c

Answer 2

But i feel as though i am getting it wrong.

Answer 3

quadratic formula is

x = -b +/- sqrt (b^2 - 4ac)
-------------------
2a

where a , b and c are the numbers in the equation
ax^2 + bx + c = 0

Answer 4

a=2
b=-10
c=3

Answer 5

so plug these in ?

Answer 6

right

Answer 7

Ok, thanks a bunch.

Answer 8

watch the signs
eg -b = - (-10)

Answer 9

I see.

Answer 10

would -b make the -10 positive 10?

Answer 11

yes

Answer 12

20--24/4

Answer 13

so 44 /4=10

Answer 14

x=10?

Answer 15

11* srry

Answer 16

you left out the sqrt
its

(10 + sqrt76 )/ 4 or ( 10 - sqrt76) / 4

perform the calculation in the parentheses first, then divid e by 4

Answer 17

OH!!!

Answer 18

silly me:)

Answer 19

what would be the square root i do not understand.

Answer 20

use your calculator - enter square root then 76

Answer 21

i see, so 11-sgrt76, but where is this 76 from?

Answer 22

2.28220211292 would be the answer

Answer 23

the 76 comes from the b^2 - 4ac of the formua:-
10^2 - 4*2*3 = 100 - 24 = 76

Answer 24

I see. Thank you for your time. :)

Answer 25

ok where did you get 2.25 from?

Answer 26

2.28 and so on?

Answer 27

11-sgrt76=2.28 sir

Answer 28

10 - sqrt76 = 10 - 8.72 - 1.28
but you now have to divide by 4

x = 1.28 / 4 = 0.32

Answer 29

hm, i see. that would be .32 OK

Answer 30

thats one root and the other is
(10 + sqrt76 )/ 4

Answer 31

i completely forgot;/

Answer 32

these quadratics can have 2 roots

Answer 33

Hm.