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A large bin of mixed nuts contains peanuts, cashews, almonds, and walnuts. Luke scoops out a bowl full of nuts and counts how many of each type he has: 18 peanuts, 8 cashews, 10 almonds, and 9 walnuts. Armando scoops out a bowl of 30 nuts. About how many should he expect to be peanuts? A. 4 B. 6 C. 9 D. 12
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@Abhisar
How many total nuts are there to start?
45
First you will have to calculate the probability of finding peanuts. Since, luke got 18 peanuts from the total 45 nuts he took out (18+8+10+9). The probability (P) of finding peanuts = 18/45. Now, Armado should expect P*30 peanuts = ?
12
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no it is look
@Abhisar what?
\(\huge \checkmark\)
good job :)
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