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Mathematics 8 Online
OpenStudy (anonymous):

A large bin of mixed nuts contains peanuts, cashews, almonds, and walnuts. Luke scoops out a bowl full of nuts and counts how many of each type he has: 18 peanuts, 8 cashews, 10 almonds, and 9 walnuts. Armando scoops out a bowl of 30 nuts. About how many should he expect to be peanuts? A. 4 B. 6 C. 9 D. 12

OpenStudy (anonymous):

@Abhisar

OpenStudy (anonymous):

How many total nuts are there to start?

OpenStudy (anonymous):

45

OpenStudy (abhisar):

First you will have to calculate the probability of finding peanuts. Since, luke got 18 peanuts from the total 45 nuts he took out (18+8+10+9). The probability (P) of finding peanuts = 18/45. Now, Armado should expect P*30 peanuts = ?

OpenStudy (anonymous):

12

OpenStudy (anonymous):

no it is look

OpenStudy (anonymous):

@Abhisar what?

OpenStudy (abhisar):

\(\huge \checkmark\)

OpenStudy (anonymous):

good job :)

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