Question

Trig :)

Answer 1

Coz f(x) have one half of the period of g(x) , f(x) have a period of pi. and f(pi/4) = 4
and they are both sine waves. f(0)=0
and because of period , x=pi f(pi) = 0 again.
so f(x) = 4sin(2x)

Answer 2

we can assume f(x) =ASin(Bx) +C where A,B,C are variables
x=0, f(x)=0 and when x=pi/4 f(x)=4 and when x= pi f(x) =0
so we can solve it for the three variables that way too

Answer 3

I'm confused...

Answer 4

sorry i assigned f(x) as f(θ ) and g(x) as g(θ )

Answer 5

It's not that....

Answer 6

I'm just not quite understanding what I have to do :(

Answer 7

ok lets try from the beginning. It says both functions are sine functions. right?
so f(θ ) takes the format of f(θ )= ASin(Bx)+C

Answer 8

I've never really learned that format....I just learned that "A" as you say is the amplitude, and B is period...what is C? O.o

Answer 9

Wait...that might just be for cos. Never mind...

Answer 10

So can you solve it now?

Answer 11

Lemme try.... :)

Answer 12

I'm just caught on the amplitude part....

Answer 13

Which one is amp.... pi/4 or 4?

Answer 14

I think 4....

Answer 15

yeah amplitude is 4

Answer 16

\(g(\theta)=2~sin~2\pi~\theta\) eh?

Answer 17

just relax its easy . this is a graph ok? a graph of a sin function. according to θ ,y or f(x) change ok?

Answer 18

Ah, yes.