what are the solutions of the equations x^2+14x=-130? (1point)
a.2,-16
b.10,-13
c.-2,16
d.no solution

Question

what are the solutions of the equations x^2+14x=-130? (1point)
a.2,-16
b.10,-13
c.-2,16
d.no solution

anonymous · Answer

i think its d but im not sure

anonymous · Answer

You can just plug in the points and if you get left side = right side that's a solution.

anonymous · Answer

b i guess this is super hard am i right

pooja195 · Answer

is this from the quiz?

anonymous · Answer

@pooja195

anonymous · Answer

no @poorja195 its not im trieg to see how i got it wrong

anonymous · Answer

wow are u guys just ignoring me ok fine i wont explain

anonymous · Answer

i sent you a messege @pflorido

anonymous · Answer

with a tiny bit of practice you can see that there is no solution to this right away
half of 14 is  7 and $7^2=49$ so we can go right to 
$$(x+7)^2=-130+49$$

anonymous · Answer

the left side is a perfect square, the right side is negative
therefore there is no real solution because any square must be greater than or equal to zero

anonymous · Answer

that's what i thought but wasn't sur bc i took this quiz and it said i was wrong