Question

n astronaut having mass 320 kg with equipment included is attempting an untethered space walk. The astronaut is initially at rest with respect to the nearby spacecraft, but discharges 30.0 g of nitrogen gas at 900.0 m/s from a portable propulsion unit. How fast is the astronaut moving after doing that?

0.36 m/s, 0.084 m/s , 27 m/s, or 84 m/s

?? :/

Answer 1

here we have to apply the momentum conservation law

Answer 2

ok!

Answer 3

so we can write this:
\[P = 0.03 \times 900 = ...\]
is the momentum of the gas discharged

Answer 4

oops..discharged gas

Answer 5

how much is P?

Answer 6

errr 27?

Answer 7

ok!

Answer 8

the momentum gained by our astronaut is:
\[P' = 320 \times V\]
where V is his velocity

Answer 9

so we can write:
\[27 = 320 \times V\]
what is V?

Answer 10

0.984375? so our solution is 0.084 m/s ?

Answer 11

\[V = \frac{{27}}{{320}} = {\text{0}}{\text{.084375}}\]

Answer 12

so V=0.084

Answer 13

so is that our final solution? :O

Answer 14

yes!

Answer 15

yay!! thank you!!

Answer 16

thank you!! :)