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How can I solve for x in this equation: ln(x) + ln(x-1) = 1
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\[\ln x \left( x-1 \right)=1\]
For left side of a equation, you can apply this property:\[\log(a)+\log(b) = \log(ab)\]
I know that it first simplifies to \[\ln (x(x-1))=1\] and then to... \[x(x-1)=e\]
solve the quadratic
Arrange, then you can apply quadratic formula.
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damn you so fast @surjithayer
Of course! Thank you both!! :D haha
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