The average commute to work (one way) is 25.5 minutes, according to the 2000 Census. If we assume that commuting minutes are normally distributed with a standard deviation of 6.1 minutes, what is the probability that a randomly selected commuter spends more than 60 minutes a day commuting (both ways)?

Just want to check that I'm doing my work right.
(60 - 50.1)/6.1 = 1.62
1.62 Z corresponds to .4474 area, which then taken out of .5 is .0526, since I'm looking for the latter portion of the graph. So 5.1%.

Question

The average commute to work (one way) is 25.5 minutes, according to the 2000 Census. If we assume that commuting minutes are normally distributed with a standard deviation of 6.1 minutes, what is the probability that a randomly selected commuter spends more than 60 minutes a day commuting (both ways)?

Just want to check that I'm doing my work right.
(60 - 50.1)/6.1 = 1.62
1.62 Z corresponds to .4474 area, which then taken out of .5 is .0526, since I'm looking for the latter portion of the graph. So 5.1%.

anonymous · Answer

that is the answer that I got