Question

Having problems with multi step equations, solving for x, or in this case b, with two sided equations. How to do this?
8 - 2 x b = -2/3 x (12 x b + 6)

Answer 1

8 - 2b = -2/3(12b + 6) --- Is this your problem ??

Answer 2

Yes

Answer 3

first we start on the right side and distribute the -2/3 through the parenthesis. Can you do that ?

Answer 4

By distribute, you mean multiply?

Answer 5

8 - 2b = -2/3(12b + 6 that's how it goes

Answer 6

yes...multiply everything in the parenthesis by -2/3

Answer 7

How would you do this without using the variable?

Answer 8

\[8-2b=-\frac{2}{3}(12b+6) \rightarrow\]

Answer 9

is this?

Answer 10

I mean leaving it out, it would be -12.

Answer 11

Yes @netlopes1

Answer 12

8 - 2b = (-2/3) * 12b + (-2/3) * 6
8 - 2b = -24/3b - 12/3 ---- reduce when you can
8 - 2b = -8b - 4
are you still following this ??

Answer 13

Not completely, you replaced b with -2/3 :P

Answer 14

\[8-2b=-\frac{2}{3}.12b - \frac{2}{3}.6 \rightarrow\]

Answer 15

where you see that ?? I did not replace b with -2/3

Answer 16

This is a distributive rule, ok?

Answer 17

Ohh, you left b but added -2/3.

Answer 18

\[8-2b=-\frac{24b}{3}-\frac{12}{3}\rightarrow do\quad you\quad understand\quad?\]

Answer 19

to get rid of the parenthesis we use the distributive property...that means you take the number right before the parenthesis and multiply it by everything in the parenthesis.
8 - 2b = -2/3 (12b + 6) =
8 - 2b = (-2/3 * 12b) + (-2/3 * 6) =
8 - 2b = (-24/3)b + (-12/3) =
8 - 2b = -8b - 4

any better understand this ??

Answer 20

ok, texaschic101

Answer 21

\[finally,\quad 8-2b=-8b-4\rightarrow6b=-12\rightarrow b=-2\]

Answer 22

you understand ?

Answer 23

\[6-3b=-\frac{3}{2}(-4b+4) \rightarrow\]

Answer 24

If you understand, answer this equation, ok? It's the same "model", I mean.