simplify x/7x+x^2
answer choices:
1/7x+x; where x≠-7
1/7x; where x≠0
1/7+x; where x≠0, -7
1/7

Question

simplify x/7x+x^2
answer choices:
1/7x+x; where x≠-7
1/7x; where x≠0
1/7+x; where x≠0, -7
1/7

nnesha · Answer

factor denominator

anonymous · Answer

btw these are all fraction

anonymous · Answer

and i know how to simplify it, but why does it have the: where x≠??

nnesha · Answer

alright what did you get at the denominator
7x+x^2 = ?

anonymous · Answer

x(x+7) ?

anonymous · Answer

wait, x+7?

nnesha · Answer

yep right now set it 
like this $$\huge\rm x(x+7) \cancel{=}0$$
denominator can't be equal to 0
bec when you can't divide anything by 0 
x/0 = undefined

nnesha · Answer

$$\huge\rm x(x+7) \cancel{=}0$$
solve for x

nnesha · Answer

set both x and (x+7)not equal to 0 $$x \cancel{=} 0  , (x+7) \cancel{=} 0$$
x can't be equal to 0
$$ \ (x+7) \cancel{=} 0$$
solve for x^

anonymous · Answer

so when it says x≠, i just have to put the numbers that come after is in for x in the equation and see if it works itself out or not?

nnesha · Answer

well x≠something for example lest's say x≠ 6
that's mean xcan't be equal to 6
bec x- 6 when u plug in 6 for x
you will get 0
6-6 = 0 that's what we don't want 
DENOMINATOR can't be equal to 0

anonymous · Answer

ohhhhhhh okay... thank you soooo much!

nnesha · Answer

np :-)