Without drawing the graph of the equation, determine how many points the parabola has in common with the x-axis and whether its vertex lies above, on, or below the x-axis.

y = x2 – 12x + 12

(Points : 4)
1 point in common; vertex on x-axis
2 points in common; vertex below x-axis
2 points in common; vertex above x-axis
no points in common; vertex above x-axis

Question

Without drawing the graph of the equation, determine how many points the parabola has in common with the x-axis and whether its vertex lies above, on, or below the x-axis.

y = x2 – 12x + 12

(Points : 4)
       1 point in common; vertex on x-axis
       2 points in common; vertex below x-axis
       2 points in common; vertex above x-axis
       no points in common; vertex above x-axis

anonymous · Answer

@KathyMae95

anonymous · Answer

Calculate the discriminant and use it to determine how many real-number roots the equation has.

3x2 – 6x + 1 = 0

(Points : 4)
       three real-number roots
       two real-number roots
       one real-number root
       no real-number roots
and then theres this one

anonymous · Answer

brb

netlopes1 · Answer

please, how is the question: x^2 -12x + 12 or 3x^2 - 6x +1?

anonymous · Answer

because and can be idiot. how else. idk why they made it like that