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OpenStudy (anonymous):
Solve each problem by using the quadratic formula. Write solutions in simplest radical form.
2x2 + 2x – 2 = 0
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pooja195 (pooja195):
list abc values
pooja195 (pooja195):
\[\huge~x=\frac{ -b \pm \sqrt{b^2-4ac} }{ 2a } \]
pooja195 (pooja195):
then plug in
OpenStudy (netlopes1):
\[x=\frac{ -b \pm \sqrt{b^2-4ac} }{ 2a } \rightarrow where \quad a=2 \quad b=2 \quad c=-2\]
OpenStudy (triciaal):
factor out 2 first
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OpenStudy (triciaal):
sorry if specified using the formula
OpenStudy (mathmate):
@triciaal I think it's better to factor out even if we use the quad. formula.
Better than later! :)
OpenStudy (mathmate):
*better now than later! :)
OpenStudy (netlopes1):
\[x=\frac{ -2 \pm \sqrt{2^2-4.2(-2)} }{ 2.2 } \rightarrow x=\frac{ -2 \pm \sqrt{4+16} }{ 4 }\]
OpenStudy (netlopes1):
\[x=\frac{ -2 \pm \sqrt{20} }{ 4 } \rightarrow x=\frac{ -2 \pm 2\sqrt{5} }{ 4 }\]
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OpenStudy (netlopes1):
\[x=\frac{ -1 + \sqrt{5} }{ 2 } \quad or \quad x=\frac{ -1 - \sqrt{5} }{ 2 }\]
OpenStudy (anonymous):
thank you so much! this really helped!
OpenStudy (netlopes1):
ok...
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