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OpenStudy (anonymous):
What is the fourth term in this multiplication pattern?
multiplication pattern using the formula 2 • 6n – 1
A.
12
B.
72
C.
432
D.
2592
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OpenStudy (anonymous):
are you asking what n is?
OpenStudy (anonymous):
if so what does this equal?
OpenStudy (anonymous):
shoot n is a exponent
OpenStudy (anonymous):
Im so stupid
OpenStudy (anonymous):
ok.. so please rewrite the Question. Im not sure what the question is. Are we solving for N? or what?
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OpenStudy (anonymous):
looks like it is: \[2\times 6^n -1\]
amd we meed to find the fourth term
OpenStudy (anonymous):
yay that
OpenStudy (anonymous):
Then sorry i cant help here/ I dont understand that. Sorreh @baconbaby1334
OpenStudy (anonymous):
or is it \[2\times 6^{(n-1)}\]????
beacause the answers dont match for the other form...
OpenStudy (anonymous):
yay I think it is that but I dont understand how that works
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OpenStudy (anonymous):
for the fourth term we just need to replace n by 4
we get:
\[2\times6^{(4-1)}=2\times6^{3}\]
can you calculate that?
OpenStudy (anonymous):
432
OpenStudy (anonymous):
great! so it is answer C !
OpenStudy (anonymous):
Thanks
OpenStudy (anonymous):
yw!
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