Question

A right triangle has base (x - 7) units and height (2x - 10) units.

Part A: What is the square of the length of the hypotenuse of the triangle? Show your work. (4 points)

Part B: What is the area of the triangle? (3 points)

Part C: Using the solution obtained in Part B, explain the closure property of multiplication of polynomials. (3 points)

Answer 1

@ganeshie8 @Nnesha @hartnn

Answer 2

Please help
Anyone

Answer 3

@mathmate @welshfella Can you guys help?
I have a general idea of what I need to do for part one, but I get really lost afterwards.

Answer 4

square of hypotenuse , by Pythagoras theorem
= sum of squares on the other 2 sides
= (x - 7^2 + (2x - 10)^2

Answer 5

I got that much, but I need to simplify it I believe

Answer 6

@welshfella

Answer 7

What do you have that you need to simplify?

Answer 8

I need the square length of the hypotenuse. so wouldn't I need to simplify (x-7)^2 + (2x+10)= C^2?

Answer 9

Like I know that much but I don't know what to do afterwards. do I square everything?

Answer 10

You need to square (x-7) and (2x-10) right now. If you have a scientific calculator you can do this easily, but if you have a reg. calculator then do (x-7)(x-7) and use the distributive property. Then do the same with (2x-10)(2x-10)