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Mathematics 12 Online
OpenStudy (stuck-help):

simplified form of the expression in the comments

OpenStudy (stuck-help):

\[\left( 3c ^{2}d ^{4} \right)^{3}x \left( 2c ^{5}d ^{8} \right)^{3}\]

OpenStudy (stuck-help):

i have no idea and need the work i have work this equation so many ways and cannot get the answer

OpenStudy (stuck-help):

@Babynini are you working this problem

OpenStudy (anonymous):

do u have ANY answer choices?

OpenStudy (anonymous):

multiply each exponent in the first expression by 3

OpenStudy (anonymous):

also in the second one

OpenStudy (stuck-help):

yes but i have to have the work i redoing the problems and have to the work

OpenStudy (stuck-help):

@satellite73 do i multiply the 3exponent on the out side of the () to the exponents on the inside or the other #s

OpenStudy (anonymous):

what does "have the work" mean? multiply is multiply the first term will become \[3^3c^6d^{12}\]

OpenStudy (anonymous):

don't forget to cube the three also

OpenStudy (stuck-help):

i have to write everything you do down

OpenStudy (anonymous):

in the second term, again multiply every exponent by 3 don't forget to cube the 2 as well

OpenStudy (anonymous):

then when you are done, add the exponents with the like bases

OpenStudy (stuck-help):

\[3^{3} +2^{3}\] add the 3 and 2 and the exponents 3 and 3

OpenStudy (babynini):

(did yall figure this out? :) )

OpenStudy (anonymous):

\[3^3c^6d^{12}\times 2^3c^{15}d^{24}\] is a start

OpenStudy (anonymous):

now add up the exponents for the c and the d

OpenStudy (stuck-help):

i did it wrong hold on so i can fix it

OpenStudy (stuck-help):

\[5^{6}2c ^{21}2d ^{35}\]

OpenStudy (stuck-help):

is what i got @satellite73

OpenStudy (anonymous):

d³⁶ *

OpenStudy (stuck-help):

yes \[2d ^{36}\]

OpenStudy (anonymous):

24+12 = 36..

OpenStudy (anonymous):

yep

OpenStudy (stuck-help):

i just wrote it wrong pressed the wrong button

OpenStudy (stuck-help):

@satellite73 is that all because that doesnt match any of my answers

OpenStudy (anonymous):

\[c^{21}d^{34}\]and in front should be \[27\times 8\]

OpenStudy (stuck-help):

how ?

OpenStudy (stuck-help):

how do you get 27*8

OpenStudy (anonymous):

\[3^3=27,2^3=8\]

OpenStudy (stuck-help):

thank you @satellite73

OpenStudy (stuck-help):

i have the answer \[216 c ^{21} d ^{36}\]

OpenStudy (stuck-help):

can you help with one more ill open it in another

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