Calculus Rates & speed question about airplanes
I know the answer of a; how do I find the equation for the distance between the planes at all times for part b?
its easier to read when its not in the chinese mode ...
yup
Is it solvable?
its solveble, buti have to read thru it first, and these old eyes get tired at times
both at 33000 ft they intersect directly over Frada hgts near misses shortly after 130pm --------------------------------------- at 130, Am2003 was 32 Nm from Frada, heading 171o at a rate of 405knots at 130 Un366 was 44 Nm from Frada, heading 81o at a rate of 465 knots
how how do we read airplane headings? from the north line right?
yes
doesnt really matter, the orientation is the same regardless of our 'proper' placements
lets draw a picture, both planes, and Frada
Ohh ok I just assumed it was a right triangle and so drew a right triangle with 81 9 and 90
171-81 = 90, so your assumption was valid
we have that, we got the rate of the distance decreasing between them two, but we need to find the actual distance separation at the closest point. that is the part we are having trouble with
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the rate we got is 472.8 knots
yup we have that already
d^2 = x^2 + y^2 rate of change is derivatives, so what is our derivative?
jut making sure we are on the same page here
the shortest distance between them is when one of them is at Frada ... that is when they are in line with each other.
what is our derivative? lets make sure we are working it thru and have not developed any errors
hmm..how did you draw the triangle?
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yup we have that
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