Question

how do i find x

Answer 1

:D just before yz

Answer 2

\[\frac{ 7x + 4}{ x }=2\]

Answer 3

Try multiply both sides by x.

Answer 4

so would it be \[7x + 4 = 2x\]

Answer 5

Yeah. Now subtract both sides by 2x.

Answer 6

Can you handle from here?

Answer 7

so \[5x + 4 = 0\]

Answer 8

@geerky42 okay so i got it but its not in my answer

Answer 9

What is your answer?

Answer 10

You need to isolate x to get your answer, so you know.

Answer 11

i know i got \[\frac{ -4 }{ 5 }\] which is also -.08 but its not in my choices

Answer 12

can i post the original question?

Answer 13

What are your choices?

Answer 14

Sure.

Answer 15

Solve for x: 5 over quantity x squared minus 4 plus 2 over x equals 2 over quantity x minus 2.

x = 8
x = –4
x = 8 and x = –4
No Solution

Answer 16

\[\frac{ 5 }{ x^2 - 4 } + \frac{ 2 }{ x } = \frac{ 2 }{ x - 2}\]

Answer 17

\(x^2-4 = (x+2)(x-2)\)

So LCD here is \((x+2)x(x-2)\)

Multiply both sides by \((x+2)x(x-2)\)

Lot of work, yeah but it's so we won't have x in denominator anymore.

Answer 18

so i have to multiply \[\frac{ 2 }{ z - 2 }\] by (x +2) and x(x - 2)?

Answer 19

i mean 2/(x-2)

Answer 20

Yeah.

Answer 21

so 2(x + 2)

Answer 22

2x(x+2)

Answer 23

x-2 cancel each other

Answer 24

left us x and x+2

Answer 25

oh yeah i forgot abiout the other x okay i see

Answer 26

At end, you should have \(5x + 2(x+2)(x-2) = 2x(x+2)\)

Answer 27

Now simplify and combine like terms.

Answer 28

would we get \[5x + 2x + 4 (x - 2) = 2x^2 + 4\]

Answer 29

I got \[5x+2x^2-8 = 2x^2+4x\]

Answer 30

Just remember that \((x+2)(x-2) = x^2-4\)

Answer 31

So for second term in left side, you have \(2(x+2)(x-2) = 2(x^2-4) = 2x^2-8\)

Makes sense so far?

Answer 32

oh yeah okay now what

Answer 33

Both sides have \(2x^2\), so you can cancel them out.

Leaving us \(5x-8 = 4x\).

Now it's simply algebra from here.

Answer 34

give me a sec to solve it plz

Answer 35

so its 8

Answer 36

Yep.

Answer 37

thnx