Question

Solve for x: 7 over 8 minus 1 over x equals 3 over 4.

x = 1
x = 2
x = 4
x = 8

Answer 1

\[\frac{ 7 }{ 8 } - \frac{ 1 }{ x } = \frac{ 3 }{ 4 }\]

Answer 2

Do the follow
7/8-3/4=1/x
7-6/8=1/x
1/8=1/x
Now you can try to finish;)

Answer 3

so we have \[\frac{ 1 }{ 8 } = \frac{ 1 }{ x }\] just to make sure

Answer 4

x = 1?

Answer 5

i mean 8

Answer 6

Sure

Answer 7

thnx i have 2 more can you help with?

Answer 8

Sure

Answer 9

post it here or in a new one?

Answer 10

Here

Answer 11

Solve for x: 2 over quantity x plus 2 plus 1 over 5 equals 6 over quantity x plus 5.

x = 0
x = –13
x = 13
x = 0 and x = 13

Answer 12

\[\frac{ 2 }{ x + 2 } + \frac{ 1 }{ 5 } = \frac{ 6 }{ x + 5 }\]

Answer 13

Use minimum multiple common
(5.2)+(x+2)/5x+10= 6/x+5

10+x+2/5x+10=6/x+5

12+x/5x+10=6/x+5

(12+x).(x+5)=6.(5x+10)

Now you can try to solve the rest

Answer 14

im stuck at 62 + x^2 = 25x

Answer 15

should i subtract x^2 from both sides

Answer 16

No, now you have to use baskara

Answer 17

idk how to do that

Answer 18

Look you made a mistake somewhere
12x+60+x^2+5x=30x+60
17x+60+x^2=30x+60
X^2+17x=30x
X^2-13x=0
So
X(x-13)=0
X=0
Or
X=13

Answer 19

D is right

Answer 20

ohh okay i see

Answer 21

can you help me with 1 more>?

Answer 22

Sure :)

Answer 23

Solve for x: 3 over 3 x plus 1 over quantity x plus 4 equals 10 over 7x .

x = –3
x = 3
x = –3 and x = 3
No Solution

Answer 24

\[\frac{ 3 }{ 3x } + \frac{ 1 }{ x + 4 } = \frac{ 10 }{ 7x }\]

Answer 25

1/x+4=10/7x-3/3x
1/x+4=10/7x-1/x
1/x+4=10-7/x
1/x+4=3x

Try to finish now

Answer 26

give me 1 sec plz

Answer 27

1/x+4=3/x
Sorry I forgot the slash

Answer 28

is it -3?

Answer 29

oh ok let me try again

Answer 30

idk what the answer is

Answer 31

X=3x+12
-2x=12
X=-6

Answer 32

but that not one of my answer choices

Answer 33

x = –3
x = 3
x = –3 and x = 3
No Solution

Answer 34

My gosh I've made a mistake
1/x+4=3/7x
7x=3x+12
4x=12
X=3

Sorry about that

Answer 35

np thnx