This is the question: use long division to find the quotient Q(x) and the remainder R(x) when P(x) is divided by d(x) and express P(x) in the form d(x)*Q(x)+R(x)

P(x) = x^3+4x^2-13x+60
d(x)=x+7

My answer was wrong:P(x)=(x+7)(x^2-3x+8)+6. somewhere in my divison, but I don't understand where. Help please!

Question

This is the question: use long division to find the quotient Q(x) and the remainder R(x) when P(x) is divided by d(x) and express P(x) in the form d(x)*Q(x)+R(x)

P(x) = x^3+4x^2-13x+60
d(x)=x+7

My answer was wrong:P(x)=(x+7)(x^2-3x+8)+6. somewhere in my divison, but I don't understand where. Help please!

anonymous · Answer

$$\begin{array}{c|cccc}
&x^2&-3x&+8
\
\hline
x+7&x^3&+4x^2&-13x&+60\
&-(x^3&+7x^2)\
\hline
&&-3x^2\
&&-(-3x^2&-21x)\
\hline
&&&8x\
&&&-(8x&+56)\
\hline
&&&&4
\end{array}$$
Let me know if the formatting is confusing.

anonymous · Answer

sweet! no that was perfect! everything I did was the same except for some reason I put 54 not 56 at the end. thank you!

anonymous · Answer

You're welcome!