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Mathematics 22 Online
OpenStudy (anonymous):

Write the equation of the graph shown. https://clackamasweb.owschools.com/media/g_ima01_2014/4/y=x%5E2+2.gif

OpenStudy (anonymous):

@myko

OpenStudy (anonymous):

any guesses? does it look familiar in any way?

OpenStudy (anonymous):

try moving it down till x axis

OpenStudy (anonymous):

its square function right?

OpenStudy (anonymous):

yes. The only catch is that when x=0 what is y=?

OpenStudy (anonymous):

i'm not sure.. is it 2?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

the "simple" square function, looks like this: \(f(x)=x^2\) but it for x=0, y=0. How do you think we could fix that?

OpenStudy (anonymous):

notice that every point of this graph is like 2 nits higher then the original

OpenStudy (anonymous):

it is lioke when you calculate the value of y for any x by \(y=x^2\), and later you add 2 units to it

OpenStudy (anonymous):

so y=0 becomes y=2, y=1 becomes y=3 and so on

OpenStudy (anonymous):

thanks

OpenStudy (anonymous):

yw

OpenStudy (anonymous):

So just to check, what did you get as your function?

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