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Mathematics 15 Online
OpenStudy (anonymous):

I NEED HELP!! WILL FAN+MEDAL!!!

OpenStudy (anonymous):

After a dreary day of rain, the sun peeks through the clouds and a rainbow forms. You notice the rainbow is the shape of a parabola. Create an equation. Use the graph below to create the equation of the rainbow parabola.

OpenStudy (anonymous):

Graph of a parabola opening down at the vertex 0 comma 36 crossing the x–axis at negative 6 comma 0 and 6 comma 0.

OpenStudy (anonymous):

@iGreen

OpenStudy (anonymous):

@HWBUSTER00 can you help me with this please?

OpenStudy (anonymous):

Here's a pic of the graph to make it easier

OpenStudy (anonymous):

@pooja195 @ganeshie8 @inowalst @TheGaMer007 @TheSmartOne @tkhunny

OpenStudy (anonymous):

What's that @Spring98

OpenStudy (andrewhouck):

i dont really think there is a reasonable explination but you can go to tuterteddy.com

OpenStudy (anonymous):

I just need help creating an equation

OpenStudy (anonymous):

using the graph

OpenStudy (andrewhouck):

let me see the graph

OpenStudy (anonymous):

Heres the graph

OpenStudy (andrewhouck):

idk thats really hard sorry!!!!!

OpenStudy (anonymous):

it's algebra 2 :/ what grade are you in?

OpenStudy (andrewhouck):

just came out of 10th

OpenStudy (anonymous):

oh ok

OpenStudy (tkhunny):

Such Parabolas' equations look like this: y = ax^2 + bx + c The also look like this: (y-k) = a(x-h)^2 Vertex is (0,36). You need to see this. (y-k) = a(x-h)^2 ==> (y-36) = a(x-0)^2 = ax^2 Okay, we have (y-36) = ax^2 What do you propose to find 'a'?

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