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Mathematics 14 Online
OpenStudy (anonymous):

I need help

OpenStudy (anonymous):

OpenStudy (anonymous):

I think its c but I'm not sure

OpenStudy (anonymous):

@abdul_shabeer

OpenStudy (igreen):

Plug in x + 3 for 'y' in the first equation

OpenStudy (igreen):

\(\sf -x - (x + 3) = 1\) Solve for 'x'..can you do that?

OpenStudy (anonymous):

-1, 2?

OpenStudy (igreen):

No, don't guess.. do you know what -x - x is?

OpenStudy (igreen):

It's the same as -1 - 1, but you put an 'x' next to it..so what's -1 - 1?

OpenStudy (anonymous):

im not sure

OpenStudy (igreen):

You don't know what -1 - 1 is?

OpenStudy (anonymous):

-2

OpenStudy (igreen):

Yes..so -x - x = -2x

OpenStudy (igreen):

So we have: \(\sf -2x - 3 = 1\) Add 3 to both sides

OpenStudy (anonymous):

1 - 3 +4 ?

OpenStudy (igreen):

???

OpenStudy (anonymous):

added 3 to both sides

OpenStudy (igreen):

\(\sf -2x - 3 + 3 = 1 + 3\) \(\sf -2x \cancel{- 3 + 3} = 1 + 3\)

OpenStudy (igreen):

Which gives us: \(\sf -2x = 1 + 3\)

OpenStudy (anonymous):

okay

OpenStudy (igreen):

1 + 3 = ?

OpenStudy (anonymous):

4

OpenStudy (igreen):

Yes, so we have: \(\sf -2x = 4\) Divide -2 to both sides.

OpenStudy (anonymous):

-0.5

OpenStudy (anonymous):

1 = -0.5

OpenStudy (igreen):

No.. \(\sf \dfrac{-2x}{-2} = \dfrac{4}{-2}\) \(\sf \dfrac{\cancel{-2}x}{\cancel{-2}} = \dfrac{4}{-2}\) \(\sf x = \dfrac{4}{-2}\) Divide

OpenStudy (anonymous):

i got -2

OpenStudy (anonymous):

x = -2

OpenStudy (igreen):

Yeah, that's our x-value..now which option has an x-value of -2?

OpenStudy (anonymous):

B and d

OpenStudy (igreen):

No..

OpenStudy (igreen):

Only one of them do..

OpenStudy (anonymous):

oh, my mistake. its b

OpenStudy (igreen):

Yep, that's our answer.

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