Mathematics
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OpenStudy (anonymous):
I need help
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OpenStudy (anonymous):
OpenStudy (anonymous):
I think its c but I'm not sure
OpenStudy (anonymous):
@abdul_shabeer
OpenStudy (igreen):
Plug in x + 3 for 'y' in the first equation
OpenStudy (igreen):
\(\sf -x - (x + 3) = 1\)
Solve for 'x'..can you do that?
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OpenStudy (anonymous):
-1, 2?
OpenStudy (igreen):
No, don't guess.. do you know what -x - x is?
OpenStudy (igreen):
It's the same as -1 - 1, but you put an 'x' next to it..so what's -1 - 1?
OpenStudy (anonymous):
im not sure
OpenStudy (igreen):
You don't know what -1 - 1 is?
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OpenStudy (anonymous):
-2
OpenStudy (igreen):
Yes..so -x - x = -2x
OpenStudy (igreen):
So we have:
\(\sf -2x - 3 = 1\)
Add 3 to both sides
OpenStudy (anonymous):
1 - 3 +4 ?
OpenStudy (igreen):
???
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OpenStudy (anonymous):
added 3 to both sides
OpenStudy (igreen):
\(\sf -2x - 3 + 3 = 1 + 3\)
\(\sf -2x \cancel{- 3 + 3} = 1 + 3\)
OpenStudy (igreen):
Which gives us:
\(\sf -2x = 1 + 3\)
OpenStudy (anonymous):
okay
OpenStudy (igreen):
1 + 3 = ?
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OpenStudy (anonymous):
4
OpenStudy (igreen):
Yes, so we have:
\(\sf -2x = 4\)
Divide -2 to both sides.
OpenStudy (anonymous):
-0.5
OpenStudy (anonymous):
1 = -0.5
OpenStudy (igreen):
No..
\(\sf \dfrac{-2x}{-2} = \dfrac{4}{-2}\)
\(\sf \dfrac{\cancel{-2}x}{\cancel{-2}} = \dfrac{4}{-2}\)
\(\sf x = \dfrac{4}{-2}\)
Divide
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OpenStudy (anonymous):
i got -2
OpenStudy (anonymous):
x = -2
OpenStudy (igreen):
Yeah, that's our x-value..now which option has an x-value of -2?
OpenStudy (anonymous):
B and d
OpenStudy (igreen):
No..
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OpenStudy (igreen):
Only one of them do..
OpenStudy (anonymous):
oh, my mistake. its b
OpenStudy (igreen):
Yep, that's our answer.